x^2+6x-1024=0

Solution for x^2+6x-1024=0 equation:

x^2+6x-1024=0

a = 1; b = 6; c = -1024;
Δ = b2-4ac
Δ = 62-4·1·(-1024)
Δ = 4132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4132}=\sqrt{4*1033}=\sqrt{4}*\sqrt{1033}=2\sqrt{1033}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{1033}}{2*1}=\frac{-6-2\sqrt{1033}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{1033}}{2*1}=\frac{-6+2\sqrt{1033}}{2}
$